4x^2-18x=36

Solution for 4x^2-18x=36 equation:

4x^2-18x=36

We move all terms to the left:

4x^2-18x-(36)=0

a = 4; b = -18; c = -36;
Δ = b2-4ac
Δ = -182-4·4·(-36)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-30}{2*4}=\frac{-12}{8}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+30}{2*4}=\frac{48}{8}
=6
$